• 8 months ago
CE NOV 2023 - Find the expected production in loose cu.m (LCM) per hour of a small hydraulic excavator. Heaped bucket capacity is 0.57 m^3 .The material is sand and gravel with a bucket fill factor of 0.95 .Job efficiency is 50 min/hr .Average depth of cut is 4.3 m. max. depth of cut is 6.1 m and average swing is 90

Hint: Production = C * S * V * B * E

Cycle output = 250 cycles per 60 min
Swing depth factor = 1.0
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CE Board MSTE Problem 5 (Mathematics, Surveying, Transportation, and Construction) - CE Nov 2023
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