Learn Programming Technique C to Master Skills - Fourth Program of Loop ( Flow Chart ) - video Dailymotion

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00:00Hi I am Sandeep today I am going to explain that how to display the odd numbers but we

00:09are not going to display the first three odd numbers this is the program of user choice

00:17how many odd numbers we have to display okay so as many odd numbers we want we can display

00:25that is according to our will okay so it's a user choice program let us understand for

00:32that I have taken three variables I have taken for odd number od to count the odd numbers

00:39I have taken i and how many times the loop is going to carry on for that I have taken

00:44an extra variable n okay I have initialized the value of od that is 1 and I have initialized

00:51the counter variable i equals to 1 now how many times the loop will carry on for that

00:57I have to input the value inside this variable n suppose I have input 3 so this loop is going

01:06to carry on for how many times three times so how many odd numbers I am going to get

01:12I am going to get three odd numbers so let us do the try run 1 less than 3 as inside

01:18n it is 3 and the value of i is 1 1 less than 3 the condition is true it will come

01:23to the yes part it's going to display 1 okay then 1 plus 2 that is what 3 so inside od

01:31it is 3 what is inside i it is 1 1 plus 1 that is what 2 so remember the values inside

01:38od it is 3 inside i it is 2 the loop will carry on 2 less than 3 the condition is true

01:46okay so it's going to print the odd number as the condition is true what was the value

01:52of od it was 3 so it's going to display 3 now it will come to this equation 3 plus 2

01:57that is what 5 just remember the values the value of od is what 5 it will come to the

02:04counter variable 2 plus 1 that is what 3 so the new value of i is what 3 earlier value

02:13is over written by the new value so the value of i is what 3 and the value of od is what

02:175 okay again the loop will carry on 3 equal to 3 as the value inside i is 3 and value

02:25of n is what 3 so 3 equal to 3 the condition is true what is inside od it is 5 so 5 is

02:33going to display okay then 5 plus 2 7 and 3 plus 1 4 again the loop will carry on 4

02:41less than 3 the condition false no and stop okay so as we have given the value of n 3

02:48so this loop carry on for 3 times if i give the value of n 2 so how many times this loop

02:55is going to carry on for 2 times let us check value of i is 1 1 less than 2 the condition

03:02is true so 1 is going to print and 1 plus 2 that is what 3 so the new value of od is

03:08what 3 1 plus 1 that is what 2 it will check here 2 equals to 2 yes the condition is true

03:17what is inside od it is 3 so 3 is going to print okay and then what 3 plus 2 5 and 2

03:24plus 1 3 so 3 less than 2 as the value of n is 2 and the value of i is 3, 3 less than

03:312 the condition will get false and then stop so we get the two odd numbers 1 and 3.

03:36So whatever the value is you are going to input inside n that times the loop is going

03:43to carry on okay for that times the loop is going to carry on I hope you understand how

03:49to use user choice program how to make it in the next video I am going to make the program

03:55the same program okay in C. Thanks